Question

A cheerleader lifts his 52.7 kg partner straight up off the ground a distance of 0.858 m before
releasing her. Assume the partner’s velocity
is zero at the beginning and the end of the lift.
The acceleration of gravity is 9.8 m/s2.
If he does this 13 times, how much work has
he done?
Answer in units of J.
Don't Round answer.

Answer 1

$$W=Nmgh$$

$$W=13(52.7)(9.8)(0.858)=5761\ J$$