Answer to Question #98063 in Physics for Sunaina
What will be the velocity of the particle that is 1.8 m away from the centre on the minutes hand clock?
1
2019-11-07T09:09:41-0500
The linear velocity
"v=\\omega R=\\frac{2\\pi }{T}R"
"=\\frac{2\\pi }{3600\\:\\rm s}\\times 1.8\\:\\rm m=0.00314\u202c \\:m\/s=3.14\\: mm\/s"
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