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Answer to Question #79054 in Physics for Dennise Hernandez
Question #79054
What is the potential difference in a circuit of 100 ma and 5 ohms?
This problem consist of using the OHMS LAW equation: V= I * R
Where:
V= potential difference in volts
R= resistance ohms
I= current in amps
I also understand that 1 ma ( milliamperage) = 0.001 amp , hence, milli meaning 10^-3, which is why it is converted to 0.1. although even after the conversions, the answer is still not right? Am i adding a step? Do i have to remove the converting step and just follow the formula as is?
I do not want the answer, i want to know how to solve it. I have tried using the triangle method but it is not the right answer.
This problem consist of using the OHMS LAW equation: V= I * R
Where:
V= potential difference in volts
R= resistance ohms
I= current in amps
I also understand that 1 ma ( milliamperage) = 0.001 amp , hence, milli meaning 10^-3, which is why it is converted to 0.1. although even after the conversions, the answer is still not right? Am i adding a step? Do i have to remove the converting step and just follow the formula as is?
I do not want the answer, i want to know how to solve it. I have tried using the triangle method but it is not the right answer.
Expert's answer
1) The conversion:
100 mA=100∙〖10〗^(-3) A=0.1 A.
2) Ohms law:
V=IR
V=(0.1)(5)=0.5 V.
100 mA=100∙〖10〗^(-3) A=0.1 A.
2) Ohms law:
V=IR
V=(0.1)(5)=0.5 V.
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#339914 on Dec 2023
Comments
Dear Dennise Hernandez, 0.5 V = 500 mV.
That's exactly what I got! Although when I Google this problem, it says that the answer is 500? Why? Multiple people have he answer as 500...… even the book? Could it be possible that maybe the book is wrong including everyone else that put it as 500.
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