Answer to Question #73542 in Physics for Lewys

Question

A torch lamp that has a current of 0.25 passing through it when the potential difference across it is 3.0 v.

Answer 1

By the definition of the electrical power, we have:
P=IV,
here, P is the electrical power supplied to the torch lamp, I=0.25 A is the current passing through the lamp, V=3.0 V is the potential difference across the lamp.
Then, we get:
P=IV=0.25 A∙3.0 V=0.75 W