While in a helicopter traveling straight up at 25m/s you accidentally drop your sunglasses when you are 30m above the ground. What is the speed of your sunglasses when they hit the ground?
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Expert's answer
2017-12-10T07:29:07-0500
Distance of sunglasses to the ground h=(v_final^2-v_initial^2)/2g So, final velocity v_final=√(v_initial^2+2gh)=√(25^2+2×9.8×30)=34.8 m⁄s.
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