Question #71709
While in a helicopter traveling straight up at 25m/s you accidentally drop your sunglasses when you are 30m above the ground. What is the speed of your sunglasses when they hit the ground?
Expert's answer
Distance of sunglasses to the ground
h=(v_final^2-v_initial^2)/2g
So, final velocity
v_final=√(v_initial^2+2gh)=√(25^2+2×9.8×30)=34.8 m⁄s.
h=(v_final^2-v_initial^2)/2g
So, final velocity
v_final=√(v_initial^2+2gh)=√(25^2+2×9.8×30)=34.8 m⁄s.
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#339914 on Dec 2023
#339914 on Dec 2023
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