Answer to Question #71649 in Physics for Surej

Question #71649

A 2m long fixed string has nodes at both ends when it vibrates in its fundamental
mode. If the distance between this nodes is 12cm. what are the number of (1) nodes
(b) anti-nodes?

Expert's answer

a) The number of nodes is
N+1=2/(0.1 )+1=21
b) The number of antinodes is
N=2/(0.1 )=20

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