Answer to Question #70439 in Other Physics for Lanz
Two men are carrying a 15.00m telephone pole that weighs 100.00kg. if the center gravity of the pole is 6.00m from the right end, and the men lift the pole at the ends, how much weight must each man support?
Total weight is
Second Condition of Equilibrium:
W_1 (l-d)=W_2 d
(mg-W_1 )=W_1 (l-d)/d
W_1=mg 1/(1+(l-d)/d)=mg d/l=(100)(9.81) 6/15=392 N.
W_2=(mg-W_1 )=(mg-mg d/l)=mg(1-d/l)=(100)(9.81)(1-6/15)=589 N.
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