# Answer to Question #68604 in Other Physics for DEEPENDRA SINGH

Question #68604

Let A vector=icapAcosu+jcapAsinu is a vector. another vector, B vector is the perpendicular to A vector, then -

1.icapBcosu+jcapBsinu

2.icapBsinu-jcapBcosu

1.icapBcosu+jcapBsinu

2.icapBsinu-jcapBcosu

Expert's answer

B vector is the perpendicular to A vector, thus,

A∙B=0

1.

(iAcosu+jAsinu )(iBcosu+jBsinu)=AB(cos^2u+sin^2u )=AB≠0

2.

(iAcosu+jAsinu )(iBsinu-jBcosu)=AB(cosusinu-sinucosu)=0

Thus, the second choice is true.

Answer: 2. iBsinu-jBcosu.

A∙B=0

1.

(iAcosu+jAsinu )(iBcosu+jBsinu)=AB(cos^2u+sin^2u )=AB≠0

2.

(iAcosu+jAsinu )(iBsinu-jBcosu)=AB(cosusinu-sinucosu)=0

Thus, the second choice is true.

Answer: 2. iBsinu-jBcosu.

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