# Answer to Question #50549 in Other Physics for Nichole

Question #50549

If the earth’s orbit has a radius of 150,000,000,000 meters, what is the mass of the sun?

Expert's answer

m*v^2/r=G*m*M/r^2 ->M=v^2*r/G

m - mass of the Earth

M = V ^ 2 * R / G, whereM - mass of the Sun,

V - velocity of the planet 30 000 m/s,

R - radius of the orbit , (1,510^8 m)

G - gravitational constant . (6,67E- 11 m ^ 3 / (kg · s ^ 2 ))

It turns 2.02E + 30 = 2.02 × 10 ^ 30 kg .

m - mass of the Earth

M = V ^ 2 * R / G, whereM - mass of the Sun,

V - velocity of the planet 30 000 m/s,

R - radius of the orbit , (1,510^8 m)

G - gravitational constant . (6,67E- 11 m ^ 3 / (kg · s ^ 2 ))

It turns 2.02E + 30 = 2.02 × 10 ^ 30 kg .

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