# Answer to Question #49772 in Other Physics for nick

Question #49772

Given a system like the one you used in lab and the following numbers for the moment of inertia of the T, the radius of the vertical bar and the hanging mass calculate the expected acceleration of the system.

I = 0.040 kg m2

r = 0.015 m

m = 0.500 kg

I = 0.040 kg m2

r = 0.015 m

m = 0.500 kg

Expert's answer

The forces on mass m are tension andgravity, so ussing Newton’s second law and expression of moment of inertia we

have:

I =( mgr

So accelerationof the system α=mgr

have:

I =( mgr

^{2}/α) − mr^{2}So accelerationof the system α=mgr

^{2}/(I+mr^{2})=0.03m/s^{2}Need a fast expert's response?

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