# Answer on Other Physics Question for irebami

Question #46639

A battery of emf E and negligible internal resistance is connected to two resistances R1 and R2 in series. What the potential difference across R2?

E(R1+R2)/R2

E(R1+R2)/R1

ER2/R1+R2

ER1/R1+R2

E(R1+R2)/R2

E(R1+R2)/R1

ER2/R1+R2

ER1/R1+R2

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