An electron is traveling at 1.9x10 m/s when it enters an electric field that slows it. The field has a mag nitude of 6200 N/C. How far does the electron penetrate the field before it stops.
The energy-work theorem says
"\\Delta E=W\\\\\n\\frac{mv^2}{2}=Fd"Hence
"d=\\frac{mv^2}{2F}=\\frac{9.1*10^{-31}*(1.9*10)^2}{2*6200}=2.6*10^{-32}\\;\\rm m"
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