# Answer to Question #28808 in Other Physics for Abhishek

Question #28808

The size of a hydrogen atom is about 0.5 Angstrom. What is total atomic volume in m3 of a mole of hydrogen atom?

Expert's answer

A mole of anything contains an Avogadro constant of constituent particles, which is about 6.022 * 10^23 particles/mole.

Thus, in one mole of atomic Hydrogen (H) there is this many H atoms. If diameter of each is about d = 0.5 A, the volume of one molecule is (assuming spherical shape)

V = (4/3)*pi*(d/2)^3 = (4/3)*pi*(0.5 * 10^(-10) m / 2)^3 = 6.545 * 10^(-32) m^3.

To get the atomic volume of a mole of H atoms, we'll multiply this elementary volume by the number of atoms in a mole:

V_a = 6.545 * 10^(-32) (m^3 / atom) * 6.022 * 10^23 (atoms / mole) = 3.94 * 10^(-8) m^3.

Thus, in one mole of atomic Hydrogen (H) there is this many H atoms. If diameter of each is about d = 0.5 A, the volume of one molecule is (assuming spherical shape)

V = (4/3)*pi*(d/2)^3 = (4/3)*pi*(0.5 * 10^(-10) m / 2)^3 = 6.545 * 10^(-32) m^3.

To get the atomic volume of a mole of H atoms, we'll multiply this elementary volume by the number of atoms in a mole:

V_a = 6.545 * 10^(-32) (m^3 / atom) * 6.022 * 10^23 (atoms / mole) = 3.94 * 10^(-8) m^3.

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