Answer to Question #271349 in Physics for FutureBSP

Question

a ball is projected with initial velocity of 18 m/s at an angle of 25 degree. what is the time of flight of the ball?

Answer 1

The time of flight is given as follows (see https://courses.lumenlearning.com/boundless-physics/chapter/projectile-motion/):

$$T = \dfrac{2u\sin\theta }{g}$$

where $u=18m/s, \theta =25\degree$ and $g = 9.8m/s^2$ is the gravitational acceleration. Thus, obtain:

$$T = \dfrac{2\cdot 18m/s\cdot \sin 25\degree}{9.8m/s^2} \approx 1.6s$$

Answer. 1.6s.