Question

A wire of length 0.75 m carries a current of 20.0 A. The wire experiences a force of 5.8 N in the presence of a magnetic field of 0.50 T. What is the angle between the magnetic field and the wire?

Answer 1

$$F_B=BILsin\theta,$$ $$\theta=sin^{-1}(\dfrac{F_B}{BIL})=sin^{-1}(\dfrac{5.8\ N}{0.50\ T\times20\ A\times0.75\ m})=50.6^{\circ}$$