A 500 grams of copper at 300 0 C and 350 grams lead at 550 0 C are put in 1200grams of aluminium container filled with one litre of water at 20 0 C. Solve for the final temperature reading.
"c_1m_1(300-t)+c_2m_2(550-t)=c_3m_3(t-20)+c_4m_4(t-20)"
"385\\cdot 0.5\\cdot(300-t)+130\\cdot 0.35\\cdot(550-t)=920\\cdot 1.2\\cdot(t-20)+4218\\cdot 1\\cdot(t-20)\\to"
"t=34\\ (\u00b0C)" . Answer
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