A wooden block of mass 1.9kg rests on a rough horizontal surface. If the limiting frictional force is 12N, calculate the coefficient of friction, take g =10m/s².
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Expert's answer
2020-11-23T10:26:30-0500
Applying the Newton’s Second Law of Motion, we get:
"\\sum F_x=ma_x=0,""F_{appl}-F_{fr}=0,""F_{appl}=F_{fr}=\\mu N = \\mu mg,""\\mu=\\dfrac{F_{fr}}{mg}=\\dfrac{12\\ N}{1.9\\ kg\\cdot 10\\ \\dfrac{m}{s^2}}=0.63"
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