Answer to Question #134428 in Physics for belal

Question

5. A porpoise jumps straight up and crashes back into the water at 8.9 m/s. The drag and buoyancy forces of the water slow the porpoise down with an acceleration of -9.3 m/s2 as the porpoise finally slows to a stop. Find the depth the porpoise reaches.

Answer 1

The distance traveled by a porpoise yo the

$$d=\frac{v^2-v_0^2}{2a}=\rm\frac{0^2-8.9^2}{2\times (-9.3)}=8.5\: m$$