For the equilibrium on the y-axis:
For the equilibrium on the x-axis:
"T\\sin \\gamma=2F\\cos {\\frac{\\alpha}{2}}=2\\frac{kq^2}{a^2}\\cos 30"
"\\tan\\gamma=2\\frac{kq^2}{mga^2}\\cos 30"
"\\cos \\gamma=\\frac{b}{L}=\\frac{\\sqrt{3}a}{4L}=\\frac{\\sqrt{3}(0.299)}{4(0.547)}"
"\\gamma=76.31\\degree"
"\\tan(76.31\\degree)=2\\frac{(8.99\\cdot 10^9)q^2}{(0.00194)(9.8)(0.299)^2}\\cos 30"
"q=1.59\\cdot 10^{-6}C"
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