Energy conservation law provides that the power, consumed from the power supply unit is all completely spent on the heat radiation. The Joule-Lentz law provides:
The flux of heat radiation equals
The tungsten energy luminosity:
"\\Phi =P=a\\sigma T^42\\pi rl"
"T=\\left(\\frac{I^2\\rho}{2a\\sigma \\pi^2r^3}\\right)^\\frac{1}{4}"
"T=\\left(\\frac{1^2(25.7\\cdot 10^{-8})}{2(0.1)(5.67\\cdot 10^{-8}) \\pi^2(0.0001) ^3}\\right)^\\frac{1}{4}=1200\\ K"
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