Answer to Question #90818 in Optics for Alex

Question

Light traveling through Air encounters a second medium which slows the light to 2.7×10 to the power of eight minutes per second what is the index of the second medium

Answer 1

the index of the second medium is given by formula

$$n= \frac { c } {v} (1)$$

where c=3×10⁸ m/s, v=2.7×10⁸ m/s

Using (1) we get: n=1.11

Answer:

1.11