Answer to Question #285649 in Optics for NICKO

Question

At what angle will 510-nm light produce a second-order maximum when falling on a grating whose slits are 1.00 x 10-3 cm apart?

Answer 1

Solution:

$\lambda=510\ nm=510\times10^{-9}\ m, \\m=2, \\d=1\times10^{-3}\ cm=10^{-5}\ m$

We know that,

$d\sin\theta=m\lambda \\ \therefore \theta=\sin^{-1}(\dfrac{m\lambda}{d}) \\ \Rightarrow \theta=\sin^{-1}(\dfrac{2\times510\times10^{-9}}{10^{-5}}) \\ \Rightarrow \theta=\sin^{-1}(0.102) \\ \Rightarrow \theta=5.85\degree$