Answer to Question #24352 in Optics for nagaraju
a ray of light incident at 15 degree on one refracting surface of angle 60 degree suffers deviation 55 degree find angle of emergence
On the first refraction,
sin (15 deg) = n*sin(60 deg)
It is then deviated by 55 degrees, so it is incident on the output surface at
n*sin(5 deg) = sin(alpha),
where alpha is the sought-for emergence angle.
alpha = arcsin( sin(5 deg) * sin(15 deg) / sin(60 deg) ) = 1.493 degrees.