62 481
Assignments Done
98,8%
Successfully Done
In June 2018

Answer to Question #22086 in Optics for khadijah

Question #22086
What mass of silver nitrate, AgNO3, is needed to make 0.50 L of a 0.10 mol/L solution?
Expert's answer
For answering this question you need to calculate amount of mol in final mixture.

0.10 mol per& 1 L
x in& 0.50 L

x=0.05 mol

Now you can calculate mass of silver nitrate, AgNO3:

n= m/Mw

m=n* Mw& ( Mw of AgNO3 = 169.87)

m=169.87 * 0.05= 8.4935

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be first!

Leave a comment

Ask Your question

Submit
Privacy policy Terms and Conditions