# Answer to Question #19381 in Optics for baran

Question #19381

if superman really had x-ray vision at 0.12nm wavelength and a 4.3mm pupil diameter,at what maximum altitude could he distinguish villains from heroes, assuming the minimum detail required was 4.8cm?

Expert's answer

Assuming the pupil to beround, the angular resolution is

sin(angle) = 1.22*wavelength/diameter;

where angle = sin(angle) = detail/distance assuming the distance is much

greater than the detail.

Thus,

distance = detail*diameter/(1.22*wavelength) = (4.8 cm)*(4.3 mm)/(1.22*0.12 nm)

= 1410 km.

Answer: 1410 kilometers.

sin(angle) = 1.22*wavelength/diameter;

where angle = sin(angle) = detail/distance assuming the distance is much

greater than the detail.

Thus,

distance = detail*diameter/(1.22*wavelength) = (4.8 cm)*(4.3 mm)/(1.22*0.12 nm)

= 1410 km.

Answer: 1410 kilometers.

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