# Answer on Optics Question for baran

Question #19161

in a interference expriment in a large ripple tank the coherent vibrating source are placed 120mm apart. the distance between maxima 2.0m away is 180mm .if the speed of ripple is 25 cm/s calculate the frequency of the vibrating source.

Expert's answer

Fringe spacing d = wavelength /sin (angle);

sin (angle) = (apart/2)/screen;

wavelength = speed/frequency;

frequency = speed/wavelength = speed*2*screen/(d*apart) = (25 cm/s) * 2 * (2 m)

/ (120 mm * 180 mm) = 46.296 Hz

Answer: 46.296 Hz

sin (angle) = (apart/2)/screen;

wavelength = speed/frequency;

frequency = speed/wavelength = speed*2*screen/(d*apart) = (25 cm/s) * 2 * (2 m)

/ (120 mm * 180 mm) = 46.296 Hz

Answer: 46.296 Hz

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