Question

while passing a slower car on the highway, you accelerate from 19.8 m/s to 27.0 m/s in a time of 10.9s. how far do you travel during this time? what is your magnitude of acceleration?

Answer 1

Solution:

Let's find the acceleration:

$a=\frac{\upsilon_2-\upsilon_1}{t}=\frac{27.0-19.8}{10.9}=0.66$ m/s².

Let's find the distance:

$S=\upsilon_1t+\frac{at^2}{2}=19.8\cdot{10.9}+\frac{0.66\cdot{(10.9)^2}}{2}=$

$=215.8+39.2=255$ m.

Answer:

S = 255 m, a = 0.66 m/s².