Answer to Question #84460 in Molecular Physics | Thermodynamics for Ra

Question

Calculate the density of bcc iron which has a lattice constant of 2.87 Å and an atomic weight of 55.85.

Answer 1

BCC structure, so n = 2

a = 2.87 Å = 2.87 x 10-10 m

(atomic weight)/ρ·10-6 = N_A/n·a3

ρ = ((55.85g/mol)·(2atoms/unit cell))/((6.023·〖10〗^23 atoms/mol)·(2.87·〖10〗^(-10) m^3)) = 6.465 g/cm3