Answer to Question #77518 in Molecular Physics | Thermodynamics for john

Question

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Answer 1

K=mv^2/2
K=3mRT/2M=3RT/Na=3kT/2
The calculation shows that for a given temperature, all gas molecules - no matter what their mass - have the same average transitional kinetic energy, namely 3kT/2.
Urms(A)/Urms(B)=√mb/ma=√5.34•10^-26/3.34•10^-27= √0.16=0.4
The temperature of the gas is proportional to the average kinetic energy of its molecules. Faster moving particles will collide with the container walls more frequently and with greater force.