# Answer to Question #65603 in Molecular Physics | Thermodynamics for samson

Question #65603

One mole of an ideal gas is heated at a constant pressure of 101300N m from 273.2 K. Calculate the work involved R=8.314 j/mol/K

Expert's answer

If the system pressure constant, it is isobaric process. For this process work is calculated as:

A=n∙R∙(T_2-T_1)

A=1∙8.314∙273.2=2271.4 J=2.271 kJ

Answer: 2.271 kJ

A=n∙R∙(T_2-T_1)

A=1∙8.314∙273.2=2271.4 J=2.271 kJ

Answer: 2.271 kJ

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