# Answer to Question #6184 in Molecular Physics | Thermodynamics for fatumata sherif

Question #6184

A kangaroo is capable of jumping to a height of 2.62 m. determine the takeoff speed of the kangaroo.

Expert's answer

Due to energy conservation law

Mgh=Mv

where M-mass of kangaroo, v- take off speedHence v=sqrt(2gh)=sqrt(2*10*2.62)=7.2 m/s

[img width=42,height=20]file:///C:/Users/Sekventa/AppData/Local/Temp/OICE_43F2E302-E2CC-470B-93D0-11F44F0047FD.0/msohtmlclip1/01/clip_image002.gif[/img]

Mgh=Mv

^{2}/2where M-mass of kangaroo, v- take off speedHence v=sqrt(2gh)=sqrt(2*10*2.62)=7.2 m/s

[img width=42,height=20]file:///C:/Users/Sekventa/AppData/Local/Temp/OICE_43F2E302-E2CC-470B-93D0-11F44F0047FD.0/msohtmlclip1/01/clip_image002.gif[/img]

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