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Answer to Question #5945 in Molecular Physics | Thermodynamics for Taylor

Question #5945
In each cycle of a Carnot engine, 242 J of heat is absorbed from the high-temperature reservoir and 121 J is exhausted to the low-temperature reservoir. What is the efficiency of the engine?
Expert's answer
The efficiency of engine is defined as ratio of the useful work done to the heat provided. We should use the following formula:
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Thus for our task we have
Efficiency = Wexh/Winp = 121/242 = 0.5.
Often efficiency is written in percentages: in our case we have 50%

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