Answer to Question #5945 in Molecular Physics | Thermodynamics for Taylor

Question #5945
In each cycle of a Carnot engine, 242 J of heat is absorbed from the high-temperature reservoir and 121 J is exhausted to the low-temperature reservoir. What is the efficiency of the engine?
1
Expert's answer
2012-01-10T10:54:37-0500
The efficiency of engine is defined as ratio of the useful work done to the heat provided. We should use the following formula:
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Thus for our task we have
Efficiency = Wexh/Winp = 121/242 = 0.5.
Often efficiency is written in percentages: in our case we have 50%

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