57 572
Assignments Done
98,9%
Successfully Done
In February 2018
Your physics homework can be a real challenge, and the due date can be really close — feel free to use our assistance and get the desired result.
Be sure that math assignments completed by our experts will be error-free and done according to your instructions specified in the submitted order form.
Our experts will gladly share their knowledge and help you with programming homework. Keep up with the world’s newest programming trends.

Answer on Molecular Physics | Thermodynamics Question for Mackenzie

Question #5464
How many kJ are needed to convert 14.4 grams of ice at -80.0 degrees Celsius to water at 61 degrees Celsius?
Expert's answer
E1 = Ci*(0-(-80))*0.0144 = 1800*80*0.0144 = 2430.72 J,
where Ci = 1800 J/kg*K is the average specific heat of an ice (from -80 to 0 degree).

E2 = Cmi*0.0144 = 334000*0.0144 = 4809.6 J,
where Cmi is specific heat of melting ice.

E3 = Cw*(61-0)*0.0144 = 4218*(61-0)*0.0144 = 3705.0912 J,
where Cw = 4218 J/kg*K is the specific heat of a clean water.

So, we need E = E1 + E2 + E3 = 2430.72 + 4809.6 + 3705.0912 = 10945.4112 J = 1.09454112 kJ to convert 14.4 grams of ice at -80.0 degrees Celsius to water at 61 degrees Celsius.

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be first!

Leave a comment

Ask Your question