Question #3849

An engine cylinder has a cross-sectional area of 0.010 m. How much work can be done by a gas

in the cylinder if the gas exerts a constant pressure of 7.5 × 105 Pa on the piston and moves the

piston a distance of 0.040 m?

in the cylinder if the gas exerts a constant pressure of 7.5 × 105 Pa on the piston and moves the

piston a distance of 0.040 m?

Expert's answer

Let S be the area of a cross-section of the cylinder, p - pressure of the gas, d = 0.04 m.

The total work can be calculated as:

A = F*d.

The force F can be found from the equation:

p = F/S, => F=p*S.

So:

A = p*S*d.

A = 7.5*10^{5}*0.01*0.04 = 300 J

So, the gas can do 300 J of work.

The total work can be calculated as:

A = F*d.

The force F can be found from the equation:

p = F/S, => F=p*S.

So:

A = p*S*d.

A = 7.5*10

So, the gas can do 300 J of work.

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