Question #37315

Water is falling from a height of 35m, Assuming that 3/4 of the K.E of the falling water gets converted to heat,then what is the rise in temperature?

Expert's answer

Kinetic energy equals change of potential energy:

E = mgh

Changes in temperature can be found as

Q=c*m*t

t=Q/(c*m)

where c is specific heat capacity, c=4200 J/(kg*K). Recalling that Q=3/4 E, we find:

t=3/4 mgh/ (c*m) = 3*9.8*35/(4*4200) = 0.06125 K

E = mgh

Changes in temperature can be found as

Q=c*m*t

t=Q/(c*m)

where c is specific heat capacity, c=4200 J/(kg*K). Recalling that Q=3/4 E, we find:

t=3/4 mgh/ (c*m) = 3*9.8*35/(4*4200) = 0.06125 K

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