Answer to Question #29789 in Molecular Physics | Thermodynamics for ana

Question

if the tempeture of 50.0L of a gas at 40.0 degrees C falls by 10.0 degrees C what is the new volume of the gas if the pressure is constant?

Answer 1

For an ideal gas at constant pressure, the volume is directly proportional to its temperature.
V₁/T₁ = V₂/T₂
where
V is volume
T is temperature (K)
V₁ = 50.0 L
T₁ = 313 K
If the temperature falls by 10.0 C, so T₂ will be = 40 - 10 = 30 C or 303 K
Therefore V₂ will be
V₂ = V₁*T₂/T₁
V₂ = 50.0 L * 303 K / 313 K = 48.40 L
Answer: V₂ = 48.40 L