# Answer to Question #29789 in Molecular Physics | Thermodynamics for ana

Question #29789

if the tempeture of 50.0L of a gas at 40.0 degrees C falls by 10.0 degrees C what is the new volume of the gas if the pressure is constant?

Expert's answer

For an ideal gas at constant pressure, the volume is directly proportional to its temperature.

V

where

V is volume

T is temperature (K)

V

T

If the temperature falls by 10.0 C, so T

Therefore V

V

V

Answer: V

V

_{1}/T_{1}= V_{2}/T_{2}where

V is volume

T is temperature (K)

V

_{1}= 50.0 LT

_{1}= 313 KIf the temperature falls by 10.0 C, so T

_{2}will be = 40 - 10 = 30 C or 303 KTherefore V

_{2}will beV

_{2}= V_{1}*T_{2}/T_{1}V

_{2}= 50.0 L * 303 K / 313 K = 48.40 LAnswer: V

_{2}= 48.40 LNeed a fast expert's response?

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