Question #29789

if the tempeture of 50.0L of a gas at 40.0 degrees C falls by 10.0 degrees C what is the new volume of the gas if the pressure is constant?

Expert's answer

For an ideal gas at constant pressure, the volume is directly proportional to its temperature.

V_{1}/T_{1} = V_{2}/T_{2}

where

V is volume

T is temperature (K)

V_{1} = 50.0 L

T_{1} = 313 K

If the temperature falls by 10.0 C, so T_{2} will be = 40 - 10 = 30 C or 303 K

Therefore V_{2} will be

V_{2} = V_{1}*T_{2}/T_{1}

V_{2} = 50.0 L * 303 K / 313 K = 48.40 L

Answer: V_{2} = 48.40 L

V

where

V is volume

T is temperature (K)

V

T

If the temperature falls by 10.0 C, so T

Therefore V

V

V

Answer: V

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