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# Answer to Question #29191 in Molecular Physics | Thermodynamics for Kaytlyn

Question #29191
At a pressure of 405 kPa, the volume of a gas is 6.00 cm3. Assuming the temperature remains constant, at what pressure will the new volume be 4.00 cm3?
1
2013-05-02T11:18:16-0400
pV = nRT
p - pressure, V - volume, n - the amount of moles, R - gs constant, T - temperature.
The gas is unknown.
In this task we speak about the same amount of gas but under different pressure. We can assume that it&#039;s mass does not change. The amount of moles is proportional to mass. That&#039;s why the amount of moles is constant too. So the amount of moles is constant. We can assume that the right part of the equation is constant. We can write:
p1V1 = p2V2
405*6 = x*4
x = (405*6)/4 = 607 kPa
That is why at the pressure 607 kPa the new volume will be 4.00 cm3.

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