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Answer to Question #2614 in Molecular Physics | Thermodynamics for Tanya Ghuman

Question #2614
In each cycle of a Carnot engine, 97 J of heat is
absorbed from the high-temperature reservoir
and 50 J is exhausted to the low-temperature
reservoir.
What is the efficiency of the engine?
Expert's answer
This maximum efficiency η is defined to be:
η= W/QH = (T1-T2)/T1 =1-T2/T1 =1-Q2/Q1

Where W is the work done by the system (energy exiting the system as work), QH is the heat put into the system (heat energy entering the system), T2 is the absolute temperature of the cold reservoir, and T1 is the absolute temperature of the hot reservoir.
So
η=1-Q2/Q1 =1-50/97=1-0.515=0.485.

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Comments

Areli
16.04.13, 02:44

405 J of heat is extracted from a massive
object at 0◦C while rejecting heat to a hot
reservoir at 21◦C.
What minimum amount of work will accomplish this?
Answer in units of J

Areli
16.04.13, 02:44

405 J of heat is extracted from a massive
object at 0◦C while rejecting heat to a hot
reservoir at 21◦C.
What minimum amount of work will accomplish this?
Answer in units of J

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