Question #21583

At what temperature will the root-mean-square speed of oxygen molecules have the value of 640 m/s? 1 kilomole of oxygen has a mass of 32kg.

Expert's answer

v =sqrt(3RT/m)

where m is molar mass (in out case 0.032 kg)

R is gas constant = 8.3

hence we have

T = v^2*m/(3R) =640^2*0.032/(3*8.3) = 526.4 K = 253.25 C

where m is molar mass (in out case 0.032 kg)

R is gas constant = 8.3

hence we have

T = v^2*m/(3R) =640^2*0.032/(3*8.3) = 526.4 K = 253.25 C

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