Question #21040

A gas has a temperature of 14 °C, and a volume of 4.5 L. If the temperature is raised to 29 °C and the pressure is not changed, what is the new volume of the gas? Round to the nearest tenth. Don't forget the units.

Expert's answer

we have isobaric process here. Hence

V1/T1 = V2/T2

where T1=14 C = (273+14) K = 287 K;

T2=29 C = (273+29) K = 302 K

V1=4.5L

V2= V1 * T2/T1 = 4.5L * 302/287 = 4.7 L

V1/T1 = V2/T2

where T1=14 C = (273+14) K = 287 K;

T2=29 C = (273+29) K = 302 K

V1=4.5L

V2= V1 * T2/T1 = 4.5L * 302/287 = 4.7 L

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