Answer to Question #205204 in Molecular Physics | Thermodynamics for Ankush

Question #205204

The standard heats of formation for CH4, CHCl3, and HCl are -74.8, -132, -92.0 KJ/mole, respectively. Use this information to calculate the heat of reaction for the following:

CH4+3Cl2=CHCl3+3HCl


1
Expert's answer
2021-06-12T10:42:13-0400


Answer: -333 kJ/mol


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