Answer on Molecular Physics | Thermodynamics Question for Bila hussa
Cice*m*(T1-T0) + Cfnice * m = Cwater*mwater*(T2-T0)
where Cice is a specific heat of ice, 2.108 J/gK , Cwater is a specific heat of water of 4.187 J/gK, Cfnice - the heat of ice fusion 333.55 J/g, T0 = 0C (melting point of ice), T1 = -10C, T2 = 20C, mwater = 0.5kg=500g.
21.08m + 333.55 m = 41870
m = 118.1 g = 0.118 kg of ice.
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