Answer to Question #139246 in Molecular Physics | Thermodynamics for Mehfooz

Question

Steam flow Steadily Into condenser Enthalpy at entry bud exit are 2050 kj/kg and 200 kj/kg respectively. Velocity at entry and exit are 500 m/s and 10 m/s. Exit is in line with Entry . Determine Heat Transfer to cooling per unit mass of steam condensed.

Answer 1

The steady flow energy equation per unit mass is:

$Q-W=H_1-H_2+\frac{(V_1^2-V_2^2)}{2}+h_2-h_1$

where

Q - Heat Transfer to cooling per unit mass,

W - external work done by system per unit mass ($W=0$),

H - Enthalpy at entry bud,

V - Velocity at entry and exit,

h - height at entry and exit ($h_2-h_1=0$).

$Q=2050-200+\frac{(500^2-10^2)}{2}=1850+124950$ $=126800\frac{J}{kg}$