Question #9907

An automobile and a truck start from rest at the same instant,with the automobile initially at some distance behind the truck.The truck has a constant acceleration of 2.20m/s2,and the automobile has an acceleration of 3.50m/s2.The automobile overtakes the truck after truck has moved 60.0m.

a)How much time does it take the automobile to overtake the truck?

b)How far the automobile behind the truck initially?

c)What is the velocity of each when they are next to each other?.

a)How much time does it take the automobile to overtake the truck?

b)How far the automobile behind the truck initially?

c)What is the velocity of each when they are next to each other?.

Expert's answer

a)How much time does it take the automobile to overtake the truck?

After t

seconds, the truck moved:

60.0 = 0.5*2.20 * t^2, so t = sqrt(2*60.0 / 2.20) =

approx. 7.385 s.

b)How far the automobile behind the truck

initially?

Let that distance was n meters.

When they met, automobile

moved:

60.0 + n = 3.50 * t^2 = 3.50 * 27.2727 = 95.4545 m, so

n = 95.4545 - 60.0 = 35.45 m.

c)What is the velocity of each when they are next to

each other?.

Truck: Vt = at * t = 2.20 * 7.385 = 16.25 m/s.

Automobile:

Va = aa * t = 3.50 * 7.385 = 25.85 m/s.

After t

seconds, the truck moved:

60.0 = 0.5*2.20 * t^2, so t = sqrt(2*60.0 / 2.20) =

approx. 7.385 s.

b)How far the automobile behind the truck

initially?

Let that distance was n meters.

When they met, automobile

moved:

60.0 + n = 3.50 * t^2 = 3.50 * 27.2727 = 95.4545 m, so

n = 95.4545 - 60.0 = 35.45 m.

c)What is the velocity of each when they are next to

each other?.

Truck: Vt = at * t = 2.20 * 7.385 = 16.25 m/s.

Automobile:

Va = aa * t = 3.50 * 7.385 = 25.85 m/s.

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## Comments

Assignment Expert17.02.17, 18:350.5*t^2 = 0.5*7.385^2 = 27.27

Anon16.02.17, 22:34how did you get 27.2727 ?

Assignment Expert10.02.16, 17:50Dear Chris, find fixed answer in the attachment.

Chris04.02.16, 21:52These are horribly wrong.

Assignment Expert25.01.16, 14:20Dear Secret Please write a new question Best regards

Smith25.01.16, 05:27Shouldn't part a be 60 = (1/2)2.2t^2? Missing a one-half there.

Secret23.01.13, 15:56Can you p[lease solve this. I hardly can't answer it. Pleaseee A car and a truck start from rest at the same instant with the car initially at some distance behind the truck. The truck has a constant acceleration of 3.4 m/s^2. The car overtakes the truck when the truck has moved a distance of 40.0 m. a. a)How much time does it take the car to overtake the truck? b)How far the car behind the truck initially? c)What is the velocity of each when they are next to each other?

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