# Answer to Question #983 in Mechanics | Relativity for brian

Question #983

A young boy swings a yo-yo horizontally above his head so that the yo-yo has a centripetal acceleration of 240 m/s[sup]2[/sup]. If the yo-yo’s string is 0.56 m long, what is the yo-yo’s tangential speed?

Expert's answer

By the equations of the rotational motion:

a= ω

ω = √(a/R) = √(240/0.56) = 20.7

Thus the linear speed would be

v = 20.7* 0.56 = 11.6 m/s

a= ω

^{2 }R ; v=ω*Rω = √(a/R) = √(240/0.56) = 20.7

Thus the linear speed would be

v = 20.7* 0.56 = 11.6 m/s

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