Question #970

It takes you all of 0.018s to initially touch and then catch a 0.600kg football travelling at 16.0m/s

a. what is the change in momentum for the football?

b. what is the impulse?

c. what is the force that must be exerted to stop the ball?

a. what is the change in momentum for the football?

b. what is the impulse?

c. what is the force that must be exerted to stop the ball?

Expert's answer

Change in the momentum: Δp = mΔv = 0.6*16 = 9.6 [kg* m/s]

The impulse equals to momentum change: I = Δp = 9.6 [kg* m/s]

The force:

F = mΔv/t = 0.600*16/0.018 = 533.33 [N]

The impulse equals to momentum change: I = Δp = 9.6 [kg* m/s]

The force:

F = mΔv/t = 0.600*16/0.018 = 533.33 [N]

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