Answer to Question #963 in Mechanics | Relativity for rissel manalo

Question #963
A car and its driver travelling at a velocity of 18 meters per second are stopped abruptly by a collision with the rear end of a packed van.The cars front end is pushed by 0.55 meters by rhe collision.The 60 kg driver who was restrained by the seat belt and shoulder strap is also stopped at 0.55 meters.Calculate a. The time the car has stopped. b. The average force acting on the driver. c. The deceleration of the drive.
1
Expert's answer
2010-11-09T09:00:09-0500
The equations of the motion:
v=v0+ at.
0 = 18 m/s - at
s=s0 +v0t - at2/2
0.55 = 18 t - at2/2
We have to solve this system of equations:
at = 18; a = 18/t
0.55 = 18t - 18t/2 = 9tt = 0.55/9 = 0.06 s.
a = 18/0.06 = 300 m/s2
F = ma = 60*300 = 18,000 Na. 0.06s b. 18,000 N c. 300 m/s2

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be first!

Leave a comment

Ask Your question

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS
paypal