Answer to Question #96178 in Mechanics | Relativity for Dhemsy

Question

The radius of the moon is one fourth and its mass is one eight first that of the earth, if the acceleration due to gravity on the surface of the earth is 9.8, what is the value on the moon surface.

Answer 1

The acceleration due to gravity on the moon surface:

$$g'=G\frac{M'}{R'^2}=G\frac{\frac{1}{81}M}{(\frac{1}{4}R)^2}=\frac{16}{81}G\frac{M}{R^2}$$

$$g'=\frac{16}{81}g=\frac{16}{81}9.8=1.9\frac{m}{s^2}$$