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Answer to Question #94314 in Mechanics | Relativity for Faris Halim

Question #94314
what is the efficiency of pump if 1500 watt and work output 12000 J in 10 seconds
Expert's answer
@$\rm efficiency=\frac{output\: work}{input\: work}@$

@$\eta=\frac{W_{output}}{W_{input}}=\frac{12000\:\rm J}{1500\:\rm W\times 10\:\rm s}=0.8=80\%@$

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