Answer to Question #84418 in Mechanics | Relativity for Yadhuraj

Question

A cricketer can throw a ball to maximum horizontal distance of 150m .How high above the ground can the cricketer throw the same ball

Answer 1

To reach the maximum horizontal distance a racketeer should throw a ball with angle

$$45^\circ$$

to horizontal. So

$$L=\frac{v_0^2\cdot sin2\alpha}{g}=\frac{v_0^2}{g}$$

To reach maximum heigh the angle must be

$$90^\circ$$

:

$$H=\frac{v_0^2\cdot sin^2\alpha}{2g}=\frac{L}{2}=75 m$$